GNU bug report logs - #79036
[PATCH] Fix pdb tracking for remote filenames

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From: Eli Zaretskii <eliz <at> gnu.org>
To: Liu Hui <liuhui1610 <at> gmail.com>
Cc: 79036 <at> debbugs.gnu.org, kobarity <at> gmail.com, michael.albinus <at> gmx.de
Subject: bug#79036: [PATCH] Fix pdb tracking for remote filenames
Date: Fri, 18 Jul 2025 17:52:54 +0300

> From: Liu Hui <liuhui1610 <at> gmail.com>
> Date: Fri, 18 Jul 2025 22:06:56 +0800
> Cc: michael.albinus <at> gmx.de, kobarity <at> gmail.com, 79036 <at> debbugs.gnu.org
> 
> On Fri, Jul 18, 2025 at 8:08 PM Eli Zaretskii <eliz <at> gnu.org> wrote:
> >
> > > file-exists-p: For a local file name in a remote python shell, we
> > > cannot simply distinguish whether it is a file on the remote system or
> > > a local file (i.e. sending code from local host), although the former
> > > is more likely. So we need file-exists-p for verification.
> >
> > Sorry, I don't understand the problem and its solution.  What do you
> > mean by "local file name in a remote python shell"?
> 
> For example, below is the pdb output in a remote python shell, and the
> file-name "/tmp/test.py" is local. Because of the "from ... import
> ...", we can know the file is on the remote system.
> 
>     >>> from test import f; f()
>     > /tmp/test.py(3)f()
>     -> return 1
>     (Pdb)
> 
> However, with the following pdb output in a remote python shell
> 
>     >>> f()
>     > /tmp/test.py(3)f()
>     -> return 1
>     (Pdb)
> 
> The local filename "/tmp/test.py" may be on the remote system like the
> above case, or may be on the local host if we press C-c C-c to send
> its code to the remote process.
> 
> Which file should python shell track? The simplest solution is to
> check which file exists.

Doesn't the value of default-directory tells us whether it's a local
or a remote file?  If not, why not?

> > > Moreover, if file doesn't exist (e.g. the original file may be
> > > deleted), it makes no sense to create an empty buffer/file, because we
> > > don't want to edit it, but to debug the code in it.
> >
> > This can be handled by other means.  But again, I don't understand why
> > is this important, so please elaborate.
> 
> I was explaining why file-exists-p is needed. It is another possible
> case.

If a file doesn't exist, debugging it will not work.  The fact that we
leave behind an empty buffer is not important.

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