GNU bug report logs - #71252
why does grep match literal newlines when there are none, even with -z?

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Message #8 received at 71252 <at> debbugs.gnu.org (full text, mbox):

From: Martin Schulte <gnu <at> schrader-schulte.de>
To: Philippe Cerfon <philcerf <at> gmail.com>
Cc: 71252 <at> debbugs.gnu.org
Subject: Re: bug#71252: why does grep match literal newlines when there are
 none, even with -z?
Date: Wed, 29 May 2024 08:08:57 +0200

Hi!

> I always thought, that grep is line based in a way that the current
> string doesn't hold the line terminator.
> If so, why does, e.g.:
>   $ printf 'foo' | grep $'\n'
>   foo
> match?

I was surprised at the first moment, too, but I think the answer is in first paragraph of the man page:

PATTERNS is one or more patterns separated by newline characters, and grep prints each line that matches a pattern.

Thus, grep $'a\nb' find all lines that either contain an a or a b.

Best regards

Martin

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