GNU bug report logs -
#65416
Feature request: include first line of file in output
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Reported by: Daniel Green <ddgreen <at> gmail.com>
Date: Mon, 21 Aug 2023 07:16:02 UTC
Severity: wishlist
Done: Paul Eggert <eggert <at> cs.ucla.edu>
Bug is archived. No further changes may be made.
Full log
Message #11 received at 65416 <at> debbugs.gnu.org (full text, mbox):
Gawk 4.0.2 is 11 years old. Try timing the current version,
I'll bet it's faster. And it solves your problem NOW,
instead of waiting for a feature that the grep developers
aren't likely to add.
My two cents of course.
Arnold
Daniel Green <ddgreen <at> gmail.com> wrote:
> That works, as well as the Perl version I've been using:
>
> perl -ne 'print if ($. == 1 || /pattern/)'
>
> But timings for a real-life example (3GB file with ~16m lines, CentOS 7)
> show the problem:
>
> grep (v2.20): ~1.15s
> perl (v5.36.1): ~4.48s
> awk (v4.0.2): ~10.81s
>
> Admittedly grep is just searching in those timings, but I suspect it could
> accomplish the full task with a minimal decrease in speed.
>
> Dan
>
> On Mon, Aug 21, 2023 at 12:57 PM <arnold <at> skeeve.com> wrote:
>
> > Daniel Green <ddgreen <at> gmail.com> wrote:
> >
> > > I'm frequently searching CSV files with 20-30 columns, and when there's a
> > > hit it can be hard to know what the columns are. An option to also print
> > > the first line of a file (either always, or only if that file had a match
> > > to the pattern) in addition to any hits would be nice.
> > >
> > > Thanks,
> > > Dan
> >
> > It sounds like awk would be a better tool:
> >
> > awk 'FNR == 1 || /pattern/' files ...
> >
> > should do the trick.
> >
> > HTH,
> >
> > Arnold
> >
This bug report was last modified 1 year and 321 days ago.
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