GNU bug report logs - #6485
Days Between Dates? How?

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Message #5 received at submit <at> debbugs.gnu.org (full text, mbox):

From: upload amritsar <upload.amritsar <at> licindia.com>
To: <bug-coreutils <at> gnu.org>
Cc: <dipakhp <at> rediffmail.com>
Subject: i have one question?
Date: Mon, 21 Jun 2010 13:49:09 +0530

Hi,
Good Morning

can you plese tell me what is the procedure or command to find the days
between two date
supoose we have 2 date first one 01-01-2008 second one 21-06-2010 then 
how can we calculate days between these two date .

Regards,
Deepak
+91-9988049558


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Message #8 received at 6485 <at> debbugs.gnu.org (full text, mbox):

From: Bob Proulx <bob <at> proulx.com>
To: upload amritsar <upload.amritsar <at> licindia.com>
Cc: dipakhp <at> rediffmail.com, 6485 <at> debbugs.gnu.org
Subject: Re: bug#6485: i have one question?
Date: Mon, 21 Jun 2010 15:47:16 -0600

retitle 6485 Days Between Dates?  How?
thanks

upload amritsar wrote:
> can you plese tell me what is the procedure or command to find the days
> between two date

If you would be so kind could you in the future address these types of
questions to coreutils <at> gnu.org instead of bug-coreutils?  The
bug-coreutils address has been changed from "all-discussion" to
"bug-discussion" and along with that change every message here now
opens a bug ticket in the bug tracking system so that we don't lose
track of reported bugs.  The coreutils <at> gnu.org address was created for
general discussion that isn't attached to the bug tracking system.
Thanks!

> supoose we have 2 date first one 01-01-2008 second one 21-06-2010 then 
> how can we calculate days between these two date .

GNU date itself doesn't include any direct support for finding days
between dates.  But it can be used as part of a script to find this
information.  The technique is to convert each date to an integer
value such as a Julian Day Number or seconds of the Unix epoch and
then do take the difference and convert back.  I will use Unix seconds
in an example.  Plus the date must be in a format that can be parsed
by GNU date.

  date1="2008-01-01"
  date2="2010-06-21"
  date1seconds=$(date -d "$date1 12:00" +%s)
  date2seconds=$(date -d "$date2 12:00" +%s)
  totalseconds=$(( $date2seconds - $date1seconds))
  secondsperday=86400
  days=$(( $totalseconds / $secondsperday ))
  echo "There were $days days between $date1 and $date2"

And of course that can be shorted up considerably by applying the
constructs inline but I wanted to make things as illustrative as
possible and so expanded them out.

  $ echo Days between dates: $(( ( $(date -d "2010-06-21 12:00" +%s) - $(date -d "2008-01-01 12:00" +%s) ) / 86400 ))

I find it is often best to do date calculations using 12:00 noon so as
to avoid any daylight savings time issues.

> "The information contained in this electronic message and any
> attachments to this message are intended for exclusive use of the
> addressee(s) and may contain confidential or privileged
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> the sender at LIC OF INDIA or co_mailadmin <at> licindia.com immediately
> and destroy all copies of this message and any attachments. The
> views expressed in this E-mail message / Attachments, are those of
> the individual sender."

Please don't post questions to public mailing lists with such a
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Bob

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