GNU bug report logs - #60659
30.0.50; tree-sitter: identical nodes are not `equal'

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Package: emacs;

Reported by: Mickey Petersen <mickey <at> masteringemacs.org>

Date: Sun, 8 Jan 2023 14:56:02 UTC

Severity: normal

Found in version 30.0.50

Done: Yuan Fu <casouri <at> gmail.com>

Bug is archived. No further changes may be made.

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Message #14 received at 60659 <at> debbugs.gnu.org (full text, mbox):

From: Yuan Fu <casouri <at> gmail.com>
To: Eli Zaretskii <eliz <at> gnu.org>
Cc: 60659 <at> debbugs.gnu.org
Subject: Re: bug#60659: 30.0.50; tree-sitter: identical nodes are not `equal'
Date: Mon, 9 Jan 2023 21:56:19 -0800
[Message part 1 (text/plain, inline)]
Mickey Petersen <mickey <at> masteringemacs.org> writes:

> Yuan Fu <casouri <at> gmail.com> writes:
>
>> Mickey Petersen <mickey <at> masteringemacs.org> writes:
>>
>>> In order to check for node equality, one must use `treesit-node-eq'.
>>>
>>> But I see little reason why two identical nodes in in the same tree aren't `equal'?
>>
>> Indeed. I’ll see if I can extend equal to handle tree-sitter nodes.
>>
>
> Nice one. This will allow for membership checks with `member' and
> such-like and it'll greatly cut down on custom code, particularly one
> you start writing tests!
>
>> Yuan

Eli, does this look right to you? In particular, I’m not sure if it’s ok to call a lisp function (Ftreesit_node_eq) inside internal_equal, even though it never signals. 

Yuan

[equal.diff (application/octet-stream, attachment)]

This bug report was last modified 2 years and 188 days ago.

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