GNU bug report logs -
#45570
operating-system definitions allow duplicate passwd and group entries
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Reported by: Jason Conroy <conjaroy <at> gmail.com>
Date: Thu, 31 Dec 2020 18:15:02 UTC
Severity: normal
Done: Leo Prikler <leo.prikler <at> student.tugraz.at>
Bug is archived. No further changes may be made.
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Hi,
Am Mittwoch, den 06.01.2021, 14:32 +0100 schrieb Ludovic Courtès:
> Hi,
>
> Leo Prikler <leo.prikler <at> student.tugraz.at> skribis:
>
> > > > + ((first . rest)
> > > > + (if (member first rest =) ; (srfi srfi-1) member
> > > > + (cons first (find-duplicates rest =))
> > > > + (find-duplicates rest =)))))
> > >
> > > Note that this is quadratic; it’s fine as long as we don’t have
> > > “too
> > > many” users, which may be the case in general.
> > It is indeed quadratic, but would there even be an n log n
> > solution?
> > I've once done an n log n sort+delete-duplicates!, perhaps that'd
> > be a
> > nicer solution here?
>
> You could first build a hash table or vhash or set with all the
> names,
> then traverse again the list of names and check whether they’re in
> that
> table. That’d be linear (assuming the table is well balanced), but
> the
> constant factor would be higher.
Yeah, I think the hash table solution would make the most sense here.
Since VHashes are based on VLists, they're not actually purely
functional, are they?
> > > (define (assert-unique-account-names users)
> > > (match (find-duplicates things …)
> > > (() #t)
> > > (lst
> > > (raise (formatted-message (G_ "the following accounts
> > > appear
> > > more than once:~{ ~a~}~%"
> > > lst))))))
> > >
> > > ?
> > That'd be weird for duplicate duplicates, hence just reporting the
> > first.
>
> You could do (delete-duplicates lst) in the message above?
Sure, but that'd be O(n^2) on top of O(n^2), which is less than ideal.
I think I'll try working on a hash-based implementation for now.
Regards,
Leo
This bug report was last modified 4 years and 217 days ago.
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