GNU bug report logs -
#41279
26.3; Calc: sum(gcd(0,n),n,-1,-1) evaluates to -1
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Reported by: David Ongaro <david.ongaro <at> hamburg.de>
Date: Fri, 15 May 2020 04:54:02 UTC
Severity: normal
Found in version 26.3
Done: Mattias EngdegÄrd <mattiase <at> acm.org>
Bug is archived. No further changes may be made.
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Message #16 received at 41279-done <at> debbugs.gnu.org (full text, mbox):
15 maj 2020 kl. 19.44 skrev David Ongaro <david.ongaro <at> hamburg.de>:
> I see, so the simplest reproduction of the bug doesn't involve the sum, but just the evaluation of gcd(0, x) or gcd(x, 0). Your fix seems sensible to me, I don't see why you consider it a 'hack'. The simplification gcd(0, x)=gcd(x, 0)=abs(x) seems legit and matches the gcd definition "The largest positive integer that divides each of the integers".
Quite, but there is a small possibility that further simplification relies on the gcd(0,x)=x behaviour. You never know with Calc: it is complex and everything seems interconnected. After all, abs is often an obstacle in algebraic transforms; you often end up splitting cases.
That said, it's probably the right thing to do. Now pushed to master, which means that you need to build a development snapshot from source, or apply the change (60cd6cce55) to your Emacs.
This bug report was last modified 5 years and 10 days ago.
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