GNU bug report logs - #28469
xargs arguments are not passed to grep

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From: Sergiu Bordei <sergiu.bordei <at> gmail.com>
To: 28469 <at> debbugs.gnu.org
Subject: bug#28469: xargs arguments are not passed to grep
Date: Fri, 15 Sep 2017 11:47:46 +0200

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Hello,

please find an error detected when is used a combination of "xargs" and
"grep", arguments {} are not substituted in grep construction:
expected results:
echo "inga"|grep -c "i"
1
user <at> box1:~$ a="i"; echo `echo "inga"|grep -c $a`
1

but was necessary tu use it in combination with xargs:

user <at> box1:~$ echo "i" | xargs -I{} echo $(echo {} ;a=$(echo {}) ; echo $a ;
echo "inga"|grep -c $a)
i i 0
user <at> box1:~$ echo "i" | xargs -I{} echo $(echo {} ;a=`echo {}` ; echo $a ;
echo "inga"|grep -c $a)
i i 0
user <at> box1:~$ echo "i" | xargs -I{} echo $(echo {} ;a={} ; echo $a ; echo
"inga"|grep -c $a)
i i 0
user <at> box1:~$ echo "i" | xargs  -I{} echo `echo {} ;a={} ; echo $a ; echo
"inga"|grep -c $a`
i i 0
user <at> box1:~$ echo "i" | xargs -I{} echo `echo {} ;a={} ; echo $a ; echo
"inga"|grep -c $a`
i i 0
user <at> box1:~$ echo "i" | xargs -I{} echo `echo {} ;a={} ; echo $a ; echo
"inga"|grep -c $a`
i i 0



Thanks,
Sergiu Bordei

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