GNU bug report logs - #15101
24.3.50; debugger-eval-expression broken

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From: help-debbugs <at> gnu.org (GNU bug Tracking System)
To: Helmut Eller <eller.helmut <at> gmail.com>
Subject: bug#15101: closed (Re: bug#15101: 24.3.50; debugger-eval-expression
 broken)
Date: Thu, 15 Aug 2013 17:23:03 +0000

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Your bug report

#15101: 24.3.50; debugger-eval-expression broken

which was filed against the emacs package, has been closed.

The explanation is attached below, along with your original report.
If you require more details, please reply to 15101 <at> debbugs.gnu.org.

-- 
15101: http://debbugs.gnu.org/cgi/bugreport.cgi?bug=15101
GNU Bug Tracking System
Contact help-debbugs <at> gnu.org with problems

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From: Stefan Monnier <monnier <at> iro.umontreal.ca>
To: Helmut Eller <eller.helmut <at> gmail.com>
Cc: 15101-done <at> debbugs.gnu.org
Subject: Re: bug#15101: 24.3.50; debugger-eval-expression broken
Date: Thu, 15 Aug 2013 13:21:53 -0400

> I think a good fix is to change debug.el so that point starts on the
> first line of the *Debugger* buffer rather than on the second.

I've just made that change.
Thank you,


        Stefan

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From: Helmut Eller <eller.helmut <at> gmail.com>
To: bug-gnu-emacs <at> gnu.org
Subject: 24.3.50; debugger-eval-expression broken
Date: Thu, 15 Aug 2013 13:39:55 +0200

Start Emacs with: emacs -Q --eval '(let ((foo 123)) (debug))'

Then press e. Enter foo to evaluate the local variable foo. But it
doesn't work; it only generates the error:
debugger-eval-expression: Symbol's value as variable is void: foo

This used to work fine in previous versions.


In GNU Emacs 24.3.50.2 (i686-pc-linux-gnu, GTK+ Version 2.24.10)
 of 2013-08-15 on ix
Bzr revision: 113885 xfq.free <at> gmail.com-20130815082722-3v7q6fyczifh2s97

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