Hello,

Is it expected that --ignore arg does not apply on globbed FILE ?

My goal is to avoid using grep or complex find args:

> ~/.ssh :: ls id_ed* | grep -v "\.pub$"
id_ed25519
id_ed25519.local
id_ed25519_ori

> ~/.ssh:: find . '!' -name '*.pub' -name "id_ed*"
./id_ed25519_ori
./id_ed25519.local
./id_ed25519

I tried -I (--ignore) and --hide :

> ~/.ssh:: ls -I"*.pub" id_ed*     
id_ed25519  id_ed25519.local  id_ed25519.local.pub  id_ed25519_ori  id_ed25519_ori.pub    id_ed25519.pub
> ~/.ssh:: ls --hide "*.pub" id_ed*    
id_ed25519  id_ed25519.local  id_ed25519.local.pub  id_ed25519_ori  id_ed25519_ori.pub    id_ed25519.pub

Since help text says for both options is :
 do not list implied entries matching shell PATTERN

I would expect it to occur after building the initial listing.

When I remove the globbing pattern, it seems to work as expected:

~/.ssh:: ls -I "*.pub" ./
config    id_ed25519  id_ed25519.local  id_ed25519_ori  id_rsa.local  known_hosts  known_hosts.old
~/.ssh:: ls -I "*.pub"
config    id_ed25519  id_ed25519.local  id_ed25519_ori  id_rsa.local  known_hosts  known_hosts.old

Man page says nothing about conflicts with file globbing. 
My view is obviously that this is a miss, what are yours ?

Thanks for your feedback
--

Mathias M