Subject: `seq' prints the numbers from FIRST to (maybe almost) LAST by INCREMENT
From: [email-masked]
To: [email-masked]
Date: Sat, 10 Aug 2013 21:56:19 +0800
List-Id: <debbugs-submit.debbugs.gnu.org>

(info "(coreutils) seq invocation")

        ... seq [OPTION]... FIRST INCREMENT LAST

       `seq' prints the numbers from FIRST to LAST by INCREMENT.  By
    default, each number is printed on a separate line.  When INCREMENT is
    not specified, it defaults to `1', even when FIRST is larger than LAST.
    FIRST also defaults to `1'.  So `seq 1' prints `1', but `seq 0' and
    `seq 10 5' produce no output.  Floating-point numbers may be specified.
    *Note Floating point::.

OK but I think you forgot to mention cases like

$ seq 0 5 17

Will the last value printed be
15, 17, or 20?
the user wonders. Hard to tell from the man/info page.