Hello,
Is it expected that --ignore arg does not apply on globbed FILE ?
My goal is to avoid using grep or complex find args:
> ~/.ssh :: ls id_ed* | grep -v
"\.pub$"id_ed25519id_ed25519.localid_ed25519_ori
> ~/.ssh:: find . '!' -name '*.pub' -name
"id_ed*"./id_ed25519_ori./id_ed25519.local./id_ed25519
I tried -I (--ignore) and --hide :
> ~/.ssh:: ls -I"*.pub" id_ed*     id_ed25519  id_ed25519.local
 id_ed25519.local.pub  id_ed25519_ori
 id_ed25519_ori.pub    id_ed25519.pub> ~/.ssh:: ls --hide "*.pub"
id_ed*    id_ed25519  id_ed25519.local  id_ed25519.local.pub
 id_ed25519_ori  id_ed25519_ori.pub    id_ed25519.pub
Since help text says for both options is : do not list implied entries
matching shell PATTERN
I would expect it to occur after building the initial listing.
When I remove the globbing pattern, it seems to work as expected:
~/.ssh:: ls -I "*.pub" ./config    id_ed25519  id_ed25519.local
 id_ed25519_ori  id_rsa.local  known_hosts  known_hosts.old~/.ssh:: ls
-I "*.pub"config    id_ed25519  id_ed25519.local  id_ed25519_ori
 id_rsa.local  known_hosts  known_hosts.old
Man page says nothing about conflicts with file globbing. My view is
obviously that this is a miss, what are yours ?
Thanks for your feedback--
Mathias M