Ludovic Courtès <ludo@gnu.org> writes:

> I think the ‘lzread!’ loop should look like this (the tests still pass
> with this):
>
> --8<---------------cut here---------------start------------->8---
>   (let loop ((read 0)
>              (start start))
>     (cond ((< read count)
>            (match (lz-decompress-read decoder bv start (- count read))
>              (0 (cond ((lz-decompress-finished? decoder)
>                        read)
>                       ((eof-object? (feed-decoder! decoder))
>                        (lz-decompress-finish decoder)
>                        (loop read start))
>                       (else                       ;read again
>                        (loop read start))))
>              (n (loop (+ read n) (+ start n)))))
>           (else
>            read)))
> --8<---------------cut here---------------end--------------->8---

Looks good to me!

>>            (match (lz-decompress-read decoder bv start (- count read))
>>              (0 (if (eof-object? (feed-decoder! decoder))
>>                     read
>>                     (loop read start)))
>>
>> I'm not sure I understand the above: if we read nothing, then we try
>> again?
>
> No: if we read *something*, we try again; if we read nothing, we return.

If we read nothing _and_ it is not an EOF (it can be an empty vector),
then we loop indefinitely, no?

> Thanks for your careful review, much appreciated!

You are welcome, thanks for your invaluable work!

-- 
Pierre Neidhardt
https://ambrevar.xyz/